SSC CHSL 2021 PYQ — Question 67

The correct answer is Option 2 i.e. 12.

Given:

Diameter of cylinder = 32 cm ⇒ Radius = 16 cm

Height of cylinder = 9 cm

Concept Used:

If a cylinder is melted and recast into a solid sphere, then

Volume of cylinder = Volume of sphere

Formula Used:

Volume of cylinder = $\pi r^2h$

Volume of sphere = ${4 \over 3} \pi r^3$

Explanation:

According to the given question,

Volume of cylinder = $\pi \times16^2 \times 9$

Volume of cylinder = Volume of sphere

⇒ $\pi \times16^2 \times 9$ = ${4 \over 3} \pi r^3$

⇒ r³ = 64 × 27

⇒ r = 12

Hence the required answer is 12 cm.