A solid metallic cuboid of dimensions 12 cm × 54 cm × 72 cm is melted and converted into 8 cubes of the same size. What is the sum of the lateral surface areas (in cm2) of 2 such cubes?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 2592
One knows that when something is melted and then recast then the volume remains the same.
The volume of a metallic cuboid = 8 × the volume of 1 cube.
12 × 54 × 72 = 8 × (side)3
Side of new small cubes = 18 cm
Lateral surface area of 2 such cubes = 2 × 4 × 18 × 18 = 2592.