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SSC CHSL 2022 PYQ — Question 63

SSC CHSL - 30 May 2022 - Shift 2 • Quantitative Aptitude • Q63

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A shopkeeper wanted to sell ₹3,000 worth of products. He gave two options — giving three successive discounts of 10% each, or giving a single discount of 30%. If a buyer chooses the former option how much extra/less does he pay as compared to the second option?

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Correct answer: C

Explanation

The correct answer is option 3 i.e. ₹87 extra

Given:

M.P. = ₹3,000

Discount rate in three successive discounts = 10%

Discount rate in single discount = 30%

Concept Used:

1. For successive discounts, S.P.=M.P.(100−D1100)(100−D2100)(100−D3100)S.P. = M.P. ({100 - D1 \over 100})({100 - D2 \over 100})({100 - D3 \over 100})

2. For single discount, S.P.=M.P.(100−D100)S.P. = M.P. ({100 - D \over 100})

Explanation:

For the successive discounts, (S.P.)1=3000(100−10100)(100−10100)(100−10100)(S.P.)_1 = 3000 ({ 100 - 10 \over 100})({100 - 10 \over 100})({100 - 10 \over 100})

⇒ (S.P.)1 = 3000 × (90/100) × (90/100) × (90/100)

⇒ (S.P.)1 = 3 × 729

⇒ (S.P.)1 = 2187

Now,  for single discount, (S.P.)2=M.P.×(100−30100)(S.P.)_2 = M.P. × ({100 - 30 \over 100})

⇒ (S.P.)2 = 3000 × (70/100)

⇒ (S.P.)2 = 30 × 70

⇒ (S.P.)2 = 2100

Therefore the difference, (S.P.)1 - (S.P.)2 = 2187 - 2100 = 87.

Hnece the buyer has to pay ₹87 extra when he choses the former option.