SSC CHSL 2024 PYQ — Question 64

SSC CHSL - 01 July 2024 - Shift 1 • Quantitative Aptitude • Q64

A shopkeeper marks up the price of the oil by 40% and uses a faulty machine which measures 15% less. If the shopkeeper gives a discount of 32%, the profit/loss percentage is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 12% Profit.

Let's cost price (CP) = 100

Marked price (MP) = 100 + 40% of 100

⇒ MP = 100 + 40

⇒ MP = 140

The faulty machine measures 15% less, so the customer gets only 85% of the quantity.

Discount % = (Marked Price - Selling Price)/Marked Price × 100

Selling price before discount (SP) = 140

 Discount given =  32% × 140

Discount = 0.32 × 140

Discount = 44.8

Selling price after discount = 140 - 44.8 = 95.2

Effective quantity sold = 85% of CP = 85% of 100

Effective quantity sold = 85

Profit = SP - Effective CP

 Profit = 95.2 - 85

⇒ Profit = 10.2

Profit percentage = Profit/cost price × 100 = (10.2/85)×100

⇒ Profit percentage = 12%