SSC Selection Post 2020 PYQ — Question 64

SSC Selection Post - Graduation Level 2020 - 9 Nov 2020 - Shift 3 • Quantitative Aptitude • Q64

A person rows a distance of 20 km upstream and 15 km downstream in a total time of 25122\frac{5}{12} hours. If the speed of the current is 4 km/h, then in how many hours can he row a distance of 64 km upstream?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 5135\frac{1}{3}.

Let boat speed in still water = x km/h

20/(x - 4) + 15/(x + 4) = 29/12

⇒ 29x2 - 420x - 704 = 0

⇒ x = [420 ± √[4202 - 4 × 29 × (-704)]/58

= [420 ± 508]/58

= (420 + 508)/58

= 16 km/h

Upstream speed = x - 4 = 16 - 4 = 12 km/h

Time for 64 km upstream = 64/12 = 5135\frac{1}{3} hours