A number is first increased by 10% and then increased by 20%. The number, so obtained, is now decreased by 12%. What is the net increase or decrease percent in the original number?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 16.16% increase.
Let the number be x
Net change in percent = x + y + xy/100
Percentage change after 10% and 20% increment;
⇒ 10 + 20 + 200/100 = 30 + 2 = 32%
Percentage change after 12% decrement;
⇒ 32 - 12 - 384/100 = 20 - 3.84 = 16.16%
Hence, the net increase is 16.16%.