A mixture of 150 litres contains acid and water in the ratio 2:3. If 30 litres of the mixture is replaced with water, what will be the percentage of acid in the final mixture?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 32%.
Mixture = 150 L where Acid : Water = 2 : 3
Acid = (2/5) × 150 = 60 L
Water = 150 - 60 = 90 L
Remove 30 L mixture:
Acid removed = (2/5) × 30 = 12 L
Water removed = 30 - 12 = 18 L
Remaining: Acid = 60 – 12 = 48 L, Water = 90 – 18 = 72 L
Add 30 L water: New water = 72 + 30 = 102 L
Total mixture = 48 + 102 = 150 L
Percentage of acid = (48/150) × 100 = 32%