A is 80% more than B and C is 48 4/7 % less than the sum of A and B. BY what percent is C less than A?

A is 80% more than B and C is 48 4/7 % less than the sum…

A is 80% more than B and C is 48 $\frac{4}{7}$ % less than the sum of A and B. BY what percent is C less than A?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 20

Application

Let B be 5x.

Since A is 80% more than B,

Then, A = 5x + (5x) × 80% = 5x + 4x = 9x

C is 48 $\frac{4}{7}$ % less than the sum of A and B

And C = (9x + 5x) – (9x + 5x) × 340 / 7% = 14x – 6.8x = 7.2x

According to the question

Percentage = (A - C) / A x 100

= (9x - 7.2x) / 9x x 100

=1.8x / 9x x 100

= 20%