SSC Selection Post 2020 PYQ — Question 67

The correct answer is option 3 i.e. 78.75.

 

Since A is 60% more than B:

A = B + 60 %  of  B = B + 0.6B = 1.6B

Since C is 45% less than twice the sum of B and A, 

C = 2 ( A + B ) − 45 %  of   2 ( A + B )

⇒  C = 2 ( 1.6B + B ) − 0.45 × 2 ( 1.6B + B )

⇒$C = 2(2.6B) - 0.45 \times 2(2.6B) = 5.2B - 0.45 \times 5.2B = 5.2B - 2.34B = 2.86B$

Percentage increase  =  $\frac{C - A}{A} \times 100 = \frac{2.86B - 1.6B}{1.6B} \times 100 = \frac{1.26B}{1.6B} \times 100$

⇒ $\frac{1.26}{1.6} \times 100 = 0.7875 \times 100 = 78.75\%$