A hemisphere of lead of radius 4 cm is cast into a right circular cone of height 72 cm. What is the radius of the base of the cone?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 1.33 cm.
Given:
A hemisphere of lead of radius 4 cm is cast into a right circular cone of height 72 cm.
Concept used:
1. Volume of hemisphere 2π × Radius3
2. Volume of a cone = (π × Radius2 × Height)/3
3. The volume of the hemisphere must be equal to the volume of the cone.
Calculation:
The volume of the hemisphere = (2π × 43)/3
= 128π/3 cm³
Let the radius of the base of the right circular cone be R cm.
According to the concept,
128π/3 cm³ = (π × R × 72)/3
⇒ R2 = 16/9
⇒ R = 4/3
⇒ R ≈ 1.33
The radius of the base of the cone is 1.33 cm.