A heap of wheat is in the form of a cone whose base daimeter is 8.4 m and height is 1.75 m. The heap is to be covered by canvass. What is the area (in m2 ) of the canvas required ? ( Use π = )
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Correct answer: A
Explanation
The correct answer is option 1 i.e. 60.06
Given :
Radius = 4.2 m
Height = 1.75 m
Formula used :
(Slant height)2 = (radius)2 + (Height)2 ----- (1)
Curved surface area of cone = πrl ----- (2)
Calculations :
Using equation (1), we get
⇒ l2 = (4.2)2 + (1.75)2
⇒ l2 = 17.64 + 3.0625
⇒ l2 = 20.7025
⇒ l = 4.55 m
Using equation (2), we get
⇒ Area of the canvas = πrl
⇒ (22/7) × 4.2 × 4.55
⇒ 22 × 0.6 × 4.55
⇒ 60.06 m2