SSC CHSL 2024 PYQ — Question 57

The correct answer is option 4 i.e. 24 cm.

According to the given question,

Let the radius of the circle be r and the centre of the circle be O.

Given that, AB = CD = 10 cm

And diameter = 26 cm

Then, radius, r = 13 cm

In triangle DOM, using Pythagoras theorem,

MO² + DM² = OD²

⇒ MO² + 5² = 13²

⇒ MO² = 169 - 25

⇒ MO = 12 cm

Again in triangle BON, using Pythagoras theorem,

NO² + BN² = OB² 

⇒ NO² + 5² = 13²

⇒ NO = 12 cm

So, distance between the two chords = MO + NO

⇒ 12 + 12 = 24 cm

Hence the distance between the two chords is 24 cm.