A circle is inscribed in ΔABC, touching AB at P, BC at Q and AC at R. If AR = 5 cm, RC = 6 cm and AB = 12 cm, then the perimeter of ΔABC is:
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 36 cm
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Concept |
Understanding |
Application |
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Tangents on a circle from an external point are equal |
In the figure: CR = CQ, AR = AP, BP = BQ
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Hence, AR = AP = 5 cm CR = CQ = 6 cm PB = AB – AP = 12 – 5 = 7 cm BP = BQ = 7cm Perimeter of the triangle = AR + AP + BP + BQ + CQ + CR = 36 cm |
