A circle is inscribed in a triangle ABC. It touches the sides AB, BC and AC at the points R, P and Q respectively. If AQ = 4.5 cm, PC = 5.5 cm and BR = 6 cm, then the perimeter of the ΔABC is:
Show answer & explanation
Correct answer: C
Explanation
Correct answer is option 3 i.e. 32 cm
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Concept |
Application |
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The tangents drawn on a circle from a common point are of same length always. |
Given: AQ = 4.5 cm, PC = 5.5 cm, BR = 6 cm Tangent AR = AQ = 4.5 cm Tangent BR = BP = 6 cm Tangent CP = CQ = 5.5 cm Hence, Perimeter of ABC = AR + BR + BP + PC + CQ + QA = 4.5 + 6 + 6 + 5.5 + 5.5 + 4.5 = 32 cm |