A circle is inscribed in a quadrilateral ABCD touching sides AB, BC, CD and AD at the points P, Q, R and S, respectively. If BP = 4 cm, SD = 6 and BC = 7 cm, then the length of DC is:
Show answer & explanation
Correct answer: D
Explanation
Correct Answer is option 4 i.e. 9 cm

|
Concept |
Understanding |
Application |
|
Length of tangents drawn from common external point to a circle are equal. |
Given BP = 4 cm, SD = 6 cm BC = 7 cm |
From the given concept: DR = SD = 6 cm QB = PB = 4 cm QC = BC – QB = 7 – 4 = 3 cm RC = QC = 3 cm DC = DR + RC = 6 + 3 = 9 cm |