A can do a piece of work in 6 days. B can do it in 9 days. With the assistance of C they complete the work in 3 days. In how many days can C alone do the work?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e 18
| Understanding | Application |
| The rate of work is inversely proportional to the time taken by the person. |
Let the number of units work be LCM(9, 3, 6) = 18 The number of units works completed by A in one day = 18 / 6 ⇒ 3 units The number of units works completed by B in one day = 18 / 9 ⇒ 2 units The number of units works completed by A, B, and C in one day = 18 / 3 ⇒ 6 units Number of units completed by C = 6 - (2 + 3) ⇒ 6 - 5 = 1 unit If C completes 1 unit of work in 1 day then for 18 units of work he will take = 18 days. |