SSC MTS 2026 PYQ — Question 5

SSC MTS - 6 Feb 2026 - Shift 3 • Quantitative Aptitude • Q5

A can do a job in 20 days, B in 30 days. They work on alternate days, with A starting the job. In how many days is the job finished?

Show answer & explanation

Correct answer: C

Explanation

Given:

A = 20 days, B = 30 days; working on alternate days, with A starting first.

A's rate = 1/20, B's rate = 1/30.

Work done in 2 days = 1/20 + 1/30 = 1/12.

Work done in 10 days (5 cycles) = 5/12.

Work done in 12 days (6 cycles) = 6/12 = 1/2.

On the 13th day (A) ⇒ Total work = 1/2 + 1/20 = 11/20.

Remaining work = 9/20.

On the 14th day (B) ⇒ Work done = 1/30.

Total work = 11/20 + 1/30 = 7/12.

Remaining work = 5/12.

Now, A and B will continue working in the same manner.

Every 2 days = 1/12.

After reaching 7/12, 5 more cycles (10 days) ⇒ +5/12 = 12/12 = 1 (Complete work).

Total days = 14 + 10 = 24 days.