A can do 50% of a work in 20 days and B can do % of the same work in 40 days. Both work The remaining work is completed by C alone in 12 days.Working together, A, B and C will complete the same work in:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. days.
LCM (40, 60) = 120
Let the total work be the individual time taken by the workers.
So, the total work = 120 units
Work done by A and B together in 6 days = (120/40 + 120/60) × 6 = 30 units
Remaining work = 120 - 30 = 90 units
The efficiency of C = 90/12 = 7.5 units
Work done each day by A, B, and C together = 3 + 2 + 7.5 = 12.5 units
Working together, A, B, and C will complete the same work in = 120/12.5 = days