A and B together can do a peice of work in 12 days. A alone can do it in 18 days. In how many days B alone can do the work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 36 days
Let the total work = LCM of 18 and 12 = 36 units.
Efficiency of A = 36/18 = 2units/day.
Efficiency of A + B = 36/12 = 3 units/day.
Efficiency of B = 3 - 2 = 1 unit/day.
Time taken by B to complete the work = 36/1 = 36 days.