A 12 litre solution of acid and water contains 30% acid. How much water (in litres) must be added to get a solution having 20% acid?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e 6
Volume of mixture = 12 L
Amount of acid in the mixture = 30%
According to the given question,
The initial amount of acid in the mixture = 30% of the total volume
⇒ 30% of 12 L = 3.6 L
The amount of water in the mixture(12 - 3.6) = 8.4 L
Let the amount of water added in the mixture be x L.
Now,
⇒
⇒ 12 + x = 18
⇒ x = 6
Hence, the water to be added is 6 L.