SSC GD 2023 PYQ — Question 41

The correct answer is Option 1 i.e.  $9 {{1} \over 11}$%.

Given:

Volume of mixture = 40 L

Quantity of water = 10%

Explanation:

Quantity of alcohol in 40 litres of mixture = 10% of Volume of mixture 

⇒ 10% of 40 L = 4 L

Quantity of water in 40 litres of mixture (40 - 4) = 36 L

On adding 4 litres of water to the mixture,

New quantity of water = (36 + 4) = 40 litres

New quantity of mixture = 44 litres

Required per cent = 4/44 × 100 

⇒ 400/44 = 100/11

⇒ $9 {{1} \over 11}$%