10 years ago, a man's age was 5 times his son's age. After 2 years, twice his age will be equal to 4 times his son's age. What is the son's present age (in years)?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 14.
10 years ago,
The ratio of the man and his son = 5 : 1
After 2 years, twice his age will be equal to 4 times his son's age
So, The ratio of the man and his son = 4 : 2 = 8 : 4
8 - 5 = 12 years
3 = 12 years
1 = 4 years
So, the present age of son = 4 × 4 - 2 = 16 - 2 = 14 years