Yash can do a piece of work in 49 days and Naman can do the same work in 35 days.Saurav can do the same work in 7 days. Find the total days required to complete the same work if they work on alternate days such that Yash works on the first day, Naman works on the second day, Saurav work on the third day and then again Yash works on the fourth day and so on.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 117/7 days
Yash can do a piece of work in 49 days and Naman can do the same work in 35 days.Saurav can do the same work in 7 days.
Total work = LCM of 7, 35, and 49 = 245
Work done by Yash in a day = 245/49 = 5 units
Work done by Naman in a day = 245/35 = 7 units
Work done by Saurav in a day = 245/7 = 35 units
Amount of work done by them when they work alternatively in the order Yash, Naman, and Saurav respectively = 5 + 7 + 35 = 47 units
Amount of work done by them in 15 days = 47(5) = 235 units
Amount of work done when Yash works on the 16th day = 235 + 5 = 240 units
Remaining work = 245 - 240 = 5 units
Time taken by Naman to do 5 units of work = 5/7
Total time required to do the work = 16 5/7 days = 117/7 days