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SSC CGL 2020 PYQ — Question 71

SSC CGL - 5th March 2020 Shift 2 • Quantitative Aptitude • Q71

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((x2(x - 4)2)/((x + 4)2 - 4x)) ÷ ((x2 - 4x)3)/((x + 4)2) × (64 - x3)/(16 - x2) is equal to :

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Correct answer: C

Explanation

The correct answer is option 3 i.e (x + 4)/((x(x - 4))

Explanation:

(x2(x - 4)2)/((x + 4)2 - 4x) ÷ ((x2 - 4x)3)/((x + 4)2) × (64 - x3)/(16 - x2)

= (x2(x - 4)2)/((x | 4)2 4x) × ((x + 4)2)/((x2 4x)3) × (64 - x3)/(10 - x2)

= ((x2(x - 4)2)/((x + 4)2 - 4x) × ((x + 4)2)/((x3(x - 4)3) × (43 - x3)/(42 - x2)

= (x + 4)1/2 - 4x × ((x + 4)2)/((x(x - 4)) × ((4 - x)(42 + 4x + x2))/((4 - x)(4 + x))

= (1)/(42 + 8x + x2 - 4x) × ((x + 4))x(x - 4)) × (42 + 4x + x2)

= (1)/(42 + 4x + x2) × ((x + 4))(x(x - 4)) × (42 + 4x + x2)

= ((x + 4))/(x(x - 4))