x,y and z are divisible by 2,3 and 4, respectively. What is the highest common factor (HCF) of 6x,4y and 3z?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. At least 12.
x divisible by 2 → x = 2a
y divisible by 3 → y = 3b
z divisible by 4 → z = 4c
Calculate: 6x = 6 × 2a = 12a
4y = 4 × 3b = 12b
3z = 3 × 4c = 12c
HCF of 12a, 12b, 12c = 12 × HCF(a, b, c)
Minimum HCF(a, b, c) = 1
= 12