SSC CGL 2024 PYQ — Question 54

The correct answer is option 2 i.e. 27.

x ∝ $\frac{y^3}{z^2}$

So, x = k$\frac{y^3}{z^2}$ (where k is the constant)

x = $1\over{36}$, y = 2 and z = 3

⇒ $1\over{36}$ = k$\frac{2^3}{3^2}$ = k$\frac 8 9$

⇒ k = $1\over{32}$

⇒ x = $1\over{32}$$\frac{y^3}{z^2}$

Put the value y = 3 and z = 5,

x = $1\over{32}$× $\frac{3^3}{5^2}$= $1\over{32}$× $\frac{27}{25}$ = $\frac{27}{800}$

⇒ 800x = 27