Write the smallest digit in the blank space of a number 7_7624, so that the number formed is divisible by 3.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 1.
Let the digit in the blank space be x
Sum of the digits = 7 + x + 7 + 6 + 2 + 4 = 26 + x
So, 26 + x must be divisible by 3
If x = 1, the sum of the digits = 26 + 1 = 27 [27 is divisible by 3]
Therefore, the smallest digit that can be placed in the blank space is 1.