SSC CGL 2023 PYQ — Question 67

SSC CGL - 19 July 2023 - Shift 1 • Quantitative Aptitude • Q67

While solving a question, Suhas mistakenly took as dividend a number which was 10% less than the original dividend. He also mistakenly took as divisor a number which was 20% less than the original divisor. If the correct quotient of the original question of division was 24 and the remainder was 0, then what quotient did Suhas obtain, assuming there was no error in his calculations?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 27.

Given that

Suhas mistakenly took as dividend a number which was 10% less than the original dividend

He also mistakenly took as divisor a number which was 20% less than the original divisor.

Quotient Q = 24, Remainder R = 0

Formula used

Dividend = Divisor × Quotient + Remainder

Calculation

Let the original dividend D be 100 units

The correct Dividend = 24 divisor + 0

D = 24d

He mistakenly taken dividend D = 90% D = 0.9D

and divisor = 80% d = 0.8d

Now, Quotient Q = 0.9D/0.8d = (9/8) (D/d) = (9/8) × 24 = 27

Hence, the required quotient is 27