SSC CGL 2022 PYQ — Question 78

The correct answer is option 1 i.e. 1.

Multiply both the numerator and denominator by 3.

So, now the series is:

${{3} \over 12}$, ${{9} \over 12}$, ? ,${{15} \over 12}$ 

So, the numerators follow the logic:

3 × 3 = 9

3 × 4 = 12

3 × 5 = 15

So, the missing fraction is ${{12} \over 12}$  = 1