SSC Selection Post 2024 PYQ — Question 51

The correct answer is option 3 i.e. 88,65,747.

1) 88,65,987

⇒ Sum of digits at odd positions: 8 + 6 + 9 + 7 = 30

⇒ Sum of digits at even positions: 8 + 5 + 8 = 21

⇒ Difference = 30 - 21 = 9 (Not divisible by 11)

2) 55,78,961

⇒ Sum of digits at odd positions: 5 + 7 + 9 + 1 = 22

⇒ Sum of digits at even positions: 5 + 8 + 6 = 19

⇒ Difference = 22 - 19 = 3 (Not divisible by 11)

3) 88,65,747

⇒ Sum of digits at odd positions: 8 + 6 + 7 + 7 = 28

⇒ Sum of digits at even positions: 8 + 5 + 4 = 17

⇒ Difference = 28 - 17 = 11 (Divisible by 11)

4) 45,12,458

⇒ Sum of digits at odd positions: 4 + 1 + 4 + 8 = 17

⇒ Sum of digits at even positions: 5 + 2 + 5 = 12

⇒ Difference = 17 - 12 = 5 (Not divisible by 11)

∴ The number 88,65,747 is divisible by 11.