SSC MTS 2026 PYQ — Question 16

Given:

Numbers = 3455, 3366, 4491, 4244

Divisible by 9 ⇒ The sum of the digits is divisible by 9

Divisible by 11 ⇒ (Difference between the sums of alternate digits) is 0 or 11

3455 → 3+4+5+5 = 17 (Not divisible by 9) ⇒ No

3366 → 3+3+6+6 = 18 (Divisible by 9)

(3+6) − (3+6) = 9 − 9 = 0 (Divisible by 11)

4491 → 4+4+9+1 = 18 (Divisible by 9)

(4+9) − (4+1) = 13 − 5 = 8 (Not divisible by 11) ⇒ No

4244 → 4+2+4+4 = 14 (Not divisible by 9) ⇒ No

3366 is the only number that is divisible by both 9 and 11.