Which of the following is the smallest number divisible by 9, 12, and 15 and leaves a remainder of 4 in each case?
Show answer & explanation
Correct answer: B
Explanation
LCM = 2² × 3² × 5 = 4 × 9 × 5 = 180
N − 4 = 180
N = 180 + 4 = 184
SSC CHSL - 12 Nov 2025 - Shift 2 • Quantitative Aptitude • Q59
Which of the following is the smallest number divisible by 9, 12, and 15 and leaves a remainder of 4 in each case?
Correct answer: B
Explanation
LCM = 2² × 3² × 5 = 4 × 9 × 5 = 180
N − 4 = 180
N = 180 + 4 = 184