Which is the largest number that divides each of 1036, 1813 and 3885 without leaving any remainder?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 259.
Given that
The largest number that divides each of 1036, 1813 and 3885 without leaving any remainder
The largest number means the HCF of (1036, 1813, 3885)
The prime factorization
1036 = 4 × 259
1813 = 7 × 259
3885 = 3 × 5 × 259
Hence, the required largest number is 259