SSC CGL 2020 PYQ — Question 36

SSC CGL Tier II - Quant - 15 Nov 2020 • Quantitative Aptitude • Q36

When positive numbers x, y and z are divided by 31, the remainders are 17, 24 and 27, respectively. When (4x - 2y + 3z) is divided by 31, the remainder will be:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 8

Concept 

Dividend = Divisor x Quotient + Remainder

Application

Let quotient be 0 in each number, we get x = 17.

Similarly, we get y = 24 and z = 27

As per the question, when (4x - 2y + 3z) is divided by 31

Putting the value of x, y and z

( 4 x 17 - 2 x 24 + 3 x 27) / 31

= 101 / 31, it will leave a remainder as 8.