When a positive integer n is divided by 9, the remainder is 4. What is the remainder when (3n2 + 2n2 + 5n) is divided by 9?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 1.
Let the value of n be 13.
Now, 3n2 + 2n2 + 5n
⇒ 5n2 + 5n
⇒ 5(169) + 5(13) = 910
Dividing 910 by 9, remainder = 1