SSC GD 2025 PYQ — Question 50

SSC GD Const 2025 (English) - 13 Feb 2025 - Shift 1 • Quantitative Aptitude • Q50

 When 12, 15, 18, 20 and 25 divide the least number x, the remainder in each case was 3 but x was divisible by 7. What is the value of x?

Show answer & explanation

Correct answer: C

Explanation

 The correct answer is Option 3 i.e. 903

Let the number be x

When divided by 12, 15, 18, 20, 25, remainder = 3 → x − 3 divisible by 12, 15, 18, 20, 25

LCM of 12, 15, 18, 20, 25 = 22 × 32 × 52 = 900

x − 3 = 900k → x = 900k + 3

x divisible by 7 → 900k + 3 ≡ 0 mod 7

900 mod 7 = 4 → 4k + 3 ≡ 0 mod 7

4k ≡ 4 mod 7 → k = 1

x = 900 × 1 + 3 = 903