What will be the least value of x so that the 5-digit number 627x5 becomes divisible by 9?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 7.
Divisibility rule of 9:- A number is divisible by 9 if the sum of its digits is divisible by 9.
The sum of the digits of the number 627x5:
⇒ 6 + 2 + 7 + x + 5 = 20 + x
For the number to be divisible by 9, 20 + x must be divisible by 9.
So, x = 7, because 7 is the smallest number,
⇒ 20 + 7 = 27 is divisible by 9
Therefore, the least value of x that makes 627x5 divisible by 9 is x = 7