SSC MTS 2026 PYQ — Question 27

SSC MTS - 18 Feb 2026 - Shift 1 • Reasoning • Q27

What was the last day of the year 1889?

Show answer & explanation

Correct answer: B

Explanation

For 1600 years: 0 odd days.

In the next 200 years (from 1601 to 1800): 3 odd days.

From 1801 to 1888 (88 years):

Leap years in 88 years = 88/4 = 22

Ordinary years = 88 - 22 = 66

Odd days = (22 x 2) + (66 x 1) = 44 + 66 = 110 days.

Remainder when 110 is divided by 7 = 5 odd days.

Year 1889 (from January 1 to December 31):

Since 1889 is an ordinary year, it contains a total of 365 days.

Remainder when 365 is divided by 7 = 1 odd day.

Total odd days:

3 (1800) + 5 (1888) + 1 (1889) = 9 odd days. Dividing 9 by 7 yields a final remainder of 2.

Day Codes:

0 = Sunday

1 = Monday

2 = Tuesday

Therefore, the correct option is B) Tuesday.