What was the day of the week on 22 October 1979?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. Monday.
Odd days in 1600 years = 0
Odd days in 300 years = 1
Odd days in 78 years = 19 leap year + 59 ordinary years = (19 × 2 + 59 × 1) = 97/7 = 6 odd day
Odd days from 1 January 1979 to 22 October 1979 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 22 = 295/7 = 1 odd days
Total odd days = 0 + 1 + 6 + 1 = 8/7 = 1 odd day
Thus, 1 is the code for 'Monday'.