What time (in seconds) is required for a 238 m long train to cross a 702 m long tunnel, if the train travels at a speed of 36 km/h?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 94
Speed = 36 × (1000 ÷ 3600) = 36 × 5 ÷ 18 = 10 m/s
Total distance to be covered = length of train + length of tunnel
Total distance = 238 + 702 = 940 m
Time = Distance ÷ Speed
Time = 940 ÷ 10 = 94 seconds