SSC GD 2025 PYQ — Question 60

SSC GD Const 2025 (English) - 18 Feb 2025 - Shift 2 • Quantitative Aptitude • Q60

What time (in seconds) is required for a 398 m long train to cross a 802 m long tunnel, if the train travels at a speed of 45 km/h?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 96 . 

Length of train = 398 m

Length of tunnel = 802 m

Total distance to cover = 398 + 802 = 1200 m

Speed = 45 km/h = 45 × 5/18 = 12.5 m/s

Time = Distance ÷ Speed = 1200 ÷ 12.5 = 96 seconds