What should be added to the each numbers 9, 22, 14, and 32 so that the obtained numbers are proportional?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 4.
Let x be added in each then, each will be in proportion such that,
(9 + x) : (22 + x) :: (14 + x) : (32 + x)
⇒ (9 + x)/(22 + x) = (14 + x)/(32 + x)
⇒ (9 + x)(32 + x) = (14 + x)(22 + x)
⇒ 288 + 9x + 32x + x2 = 308 + 14x + 22x + x2
⇒ 288 + 41x = 308 + 36x
⇒ 41x - 36x = 308 - 288
⇒ 5x = 20
⇒ x = 4