SSC GD 2024 PYQ — Question 56

SSC GD Const (English) - 26 Feb 2024 - Shift 4 • Quantitative Aptitude • Q56

What is the value of 8116÷(17616−9849)×2197169\frac{81}{16}\div\Big(\frac{176}{16}-\frac{98}{49}\Big)\times\frac{2197}{169}?

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Correct answer: B

Explanation

The correct answer is  option  2 i.e. 7.3.

(8116÷(17616−9849)×2197169)(\frac{81}{16}\div\Big(\frac{176}{16}-\frac{98}{49}\Big)\times\frac{2197}{169})

⇒ (8116÷(11−2)×2197169)(\frac{81}{16}\div ({11} -{2})\times\frac{2197}{169})

⇒ (8116÷(9)×2197169)(\frac{81}{16}\div ({9})\times\frac{2197}{169})

⇒ 8116×(19)×2197169)\frac{81}{16} \times(\frac{1}{9})\times\frac{2197}{169})

⇒ (916)×(2197169)( \frac{9}{16} )\times (\frac{2197}{169})

⇒ (197732704)( \frac{19773}{2704} )

⇒ 7.3