What is the value of 64x3 + 38x2y + 20xy2 + y3, when x = 3 and y = -4?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 1256
Given that
the value of 64x3 + 38x2y+ 20xy2 + y3
when x = 3 and y = -4
Calculation
⇒ 64x3 + 38x2y + 20xy2 + y3
⇒ 64 × 33 + 38 × 32 × (-4) + 20 × 3 × (-4)2 + (-4)3
⇒ 1728 - 1368 + 960 - 64
⇒ 2688 - 1432
⇒ 1256