SarkariPYQ

SSC GD 2024 PYQ — Question 48

SSC GD Const (English) - 29 Feb 2024 - Shift 4 • Quantitative Aptitude • Q48

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What is the value of 5128\frac{512}{8} × (240149\frac{2401}{49} - 8811\frac{88}{11}) + 2197169\frac{2197}{169} = ?

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Correct answer: C

Explanation

The correct answer is Option 3 i.e. 2637.

5128\frac{512}{8} × (240149\frac{2401}{49} - 8811\frac{88}{11}) + 2197169\frac{2197}{169} = ?

⇒ 64 × (49 - 8) + 13 = ?

⇒ 64 × 41 + 13 = ?

⇒ 2624 + 13 = ?

⇒ 2637 = ?