What is the value of 52÷25×15−15÷35×5225÷15−12×52÷254+12÷25×15\frac{\frac{5}{2}\div\frac{2}{5}\times \frac{1}{5}-\frac{1}{5}\div\frac{3}{5}\times\frac{5}{2}}{\frac{2}{5}\div\frac{1}{5}-\frac{1}{2}\times\frac{5}{2}\div \frac{25}{4}+\frac{1}{2}\div\frac{2}{5}\times \frac{1}{5}}52÷51−21×25÷425+21÷52×5125÷52×51−51÷53×25? A31/127 B32/127 C28/125 D25/123 Show answer & explanationCorrect answer: DExplanationThe correct answer is Option 4 i.e. 25/123. 52÷25×15−15÷35×5225÷15−12×52÷254+12÷25×15\frac{\frac{5}{2}\div\frac{2}{5}\times \frac{1}{5}-\frac{1}{5}\div\frac{3}{5}\times\frac{5}{2}}{\frac{2}{5}\div\frac{1}{5}-\frac{1}{2}\times\frac{5}{2}\div \frac{25}{4}+\frac{1}{2}\div\frac{2}{5}\times \frac{1}{5}}52÷51−21×25÷425+21÷52×5125÷52×51−51÷53×25 =52×52×15−15×53×5225×51−12×52×425+12×52×15=\frac{\frac{5}{2} \times \frac{5}{2} \times \frac{1}{5} - \frac{1}{5} \times \frac{5}{3} \times \frac{5}{2}}{\frac{2}{5} \times \frac{5}{1} - \frac{1}{2} \times \frac{5}{2} \times \frac{4}{25} + \frac{1}{2} \times \frac{5}{2} \times \frac{1}{5}}=52×15−21×25×254+21×25×5125×25×51−51×35×25 =54−5621−15+14= \frac{\frac{5}{4} - \frac{5}{6}}{\frac{2}{1} - \frac{1}{5} + \frac{1}{4}}=12−51+4145−65 =5124120=\frac{\frac{5}{12}}{\frac{41}{20}}=2041125 = 25/123