SSC CGL 2023 PYQ — Question 67

The correct answer is option 3 i.e. 13.

According to the given question,

$\cot A = \frac{7}{9}$

P = 9, B = 7 

Using pythagoras theorem, H = $\sqrt{49 + 81}$ = $\sqrt{130}$

Putting the values in the given expression,

$\frac{3 ({7 \over \sqrt{130}}) + 2 ({9 \over \sqrt{130}})}{3 ({7 \over \sqrt{130}}) - 2({9 \over \sqrt{130}})}$

⇒ $\frac{ {21 \over \sqrt{130}} + {18 \over \sqrt{130}}}{{21 \over \sqrt{130}} - {18 \over \sqrt{130}}}$

⇒ ${21 + 18} \over {21 - 18}$

⇒ $39 \over 3$ = 13

Hence the value of the given expression is 13.