SSC CGL 2018 PYQ — Question 97

SSC CGL Tier II Quant - 19/02/2018 • Quantitative Aptitude • Q97

What is the value of (3.6×1.62+0.48×3.6)/(1.8×0.8+10.8×0.3-2.16) ?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4, i.e. 3

= (3.6×1.62+0.48×3.6)/(1.8×0.8+10.8×0.3-2.16)

=3.6[1.62 + 0.48]/1.0×0.8+3.24-2.16

= 3.6×2.1/1.44+1.08

=3.6×2.1/2.52 = 3