What is the value of (27x3 - 58x2y + 31xy2 - 8y3), when x = -5 and y = -7?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 1924.
Given that
The value of (27x3 - 58x2y + 31xy2 - 8y3)
when x = -5 and y = -7
⇒ 27x3 - 58x2y + 31xy2 - 8y3
⇒ 27(-5)3 - 58(-52 × -7) + 31 × -5 × -72 - 8 × -73
⇒ -3375 + 58 × 175 - 7595 + 2744
⇒ -3375 + 10150 - 7595 + 2744
⇒ 12894 - 10970
⇒ 1924