What is the value of [2 cot (π – A)/2]/[1 + tan2 (2π – A)/2]?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. sin A
[2 cot(π - A)/2]/[1 + tan2(2π - A)/2]
= [2cot(π/2 - A/2)]/[1 + tan2(π - A/2)]
= 2tan (A/2)/[1 + tan2(A/2)]
= sin A (∵ 2tan2x/(1 + tan2x) = sin2x)